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The 1z1-071 Exam covers various topics such as SQL basics, data manipulation, data retrieval, table creation, and more. 1z1-071 exam is challenging and requires a deep understanding of the SQL language. Passing this certification exam demonstrates that you have the skills and knowledge needed to work with Oracle Database SQL effectively.

To be eligible to take the Oracle 1z0-071 exam, candidates must have a strong understanding of SQL concepts and should have experience working with Oracle databases. Additionally, candidates must have a basic understanding of database design and should be familiar with the concepts of normalization and data modeling.

Oracle 1z0-071 (Oracle Database SQL) Certification Exam is a widely recognized certification exam that validates the skills and knowledge of database professionals in SQL language and Oracle Database management. Oracle Database SQL certification is highly popular among IT professionals who want to enhance their career growth and demonstrate their proficiency in SQL and Oracle Database management.

Oracle Database SQL Sample Questions (Q206-Q211):

NEW QUESTION # 206
Which statement is true regarding the default behavior of the ORDER BYclause? (Choose two.)

A. Numeric values are displayed in descending order if they have decimal positions.
B. In a character sort, the values are case-sensitive.
C. NULLs are not included in the sort operation.
D. Only columns that are specified in the SELECTlist can be used in the ORDER BYclause.
E. Column aliases can be used in the ORDER BY clause.

Answer: B,E

NEW QUESTION # 207
Examine the description of the ENPLOYES table:

Which query requires explicit data type conversion?

A. SELECT join_ date + '20' EROM employees;
B. SELECT join _ date FROM employees WHERE join date > *10-02-2018';
C. SELECT SUBSTR(join date, 1, 2) - 10 FROM employees;
D. SELECT salary + '120.50' FROM employees;
E. SELECT join_ date||''|| salary FROM employees;

Answer: B

Explanation:
A look at the queries and how Oracle Database handles data type conversion:
A: This statement takes a substring of the JOIN_DATE column. Since JOIN_DATE is a DATE type and SUBSTR function expects a string, implicit conversion will occur from DATE to string based on the NLS_DATE_FORMAT setting. However, this will not require explicit conversion in the query itself.
B: This statement tries to add '20' to JOIN_DATE. Oracle Database does not support adding a string to a DATE implicitly. An explicit conversion of '20' to a number is required, or using the INTERVAL keyword to add days or years as appropriate.
C: This statement concatenates the date with an empty string and the salary. The database will implicitly convert the JOIN_DATE from a DATE to a string using the NLS_DATE_FORMAT setting and then perform the concatenation.
D: This query attempts to compare a DATE column with a string literal '*10-02-2018'. An explicit conversion using TO_DATE is needed to convert the string to a DATE data type with the appropriate date format mask. In this case, because the string does not follow the NLS_DATE_FORMAT 'DD-MON-YY', it will not be implicitly converted correctly.
E: This statement adds '120.50' to SALARY. Oracle Database will implicitly convert the string '120.50' to a number before performing the arithmetic addition, as SALARY is a NUMBER data type.

NEW QUESTION # 208
Which three statements are true regarding subqueries?

A. Subqueries can contain ORDER BY but not the GROUP BY clause.
B. Main query and subquery must get data from the same tables.
C. Subqueries can contain GROUP BY and ORDER BY clauses.
D. Only one column or expression can be compared between the main query and subquery.
E. Multiple columns or expressions can be compared between the main query and subquery.
F. Main query and subquery can get data from different tables.

Answer: C,E,F

Explanation:
References:
http://docs.oracle.com/javadb/10.6.2.1/ref/rrefsqlj13658.html

NEW QUESTION # 209
Examine the description or the CUSTOMERS table:

For Customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?

A. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers
WHERE cust_income_level != NULL AND cust_credit_level != NULL;
B. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers
WHERE cust_income_level <> NULL AND due_amount <> NULL;
C. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers
WHERE cust_income_level IS NOT NULL AND due_amount IS NOT NULL;
D. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers
WHERE cust_income_level IS NOT NULL AND cust_credit_limit IS NOT NULL;
E. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers
WHERE cust_income_level != NULL AND due_amount != NULL;

Answer: D

NEW QUESTION # 210
Examine the structure of the BOOKS_TRANSACTIONS table:

You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?

A. SELECT member_id 'MEMBER ID', due_date 'DUE DATE', '$2 AS LATE FEE' FROM BOOKS_TRANSACTIONS;
B. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", '$2' AS "LATE FEE" FROM BOOKS_TRANSACTIONS;
C. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", $2 AS "LATE FEE" FROM BOOKS_TRANSACTIONS;
D. SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE FROM BOOKS_TRANSACTIONS;

Answer: B

NEW QUESTION # 211
......

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